Medium
Write the equation of excess pressure for a liquid drop.
(N/A) For a liquid drop,there is only one free surface. The excess pressure $P$ inside a liquid drop of radius $R$ and surface tension $T$ is given by the formula:
$P = \frac{2T}{R}$
where:
$P$ is the excess pressure,
$T$ is the surface tension of the liquid,
$R$ is the radius of the liquid drop.
$P = \frac{2T}{R}$
where:
$P$ is the excess pressure,
$T$ is the surface tension of the liquid,
$R$ is the radius of the liquid drop.
Explore More
Similar Questions
When two soap bubbles of radius $r_1$ and $r_2$ $(r_2 > r_1)$ coalesce,the radius of curvature of the common surface is:
Difficult
View SolutionAn air bubble doubles in radius when it rises from the bottom of the sea to the surface. If the atmospheric pressure is equal to the pressure exerted by a $10 \, m$ column of water,then the depth of the sea is $... \, m$. (Assume surface tension is negligible.)
Difficult
View SolutionPressure inside two soap bubbles are $1.02 \ atm$ and $1.05 \ atm$ respectively. The ratio of their surface area is
Medium
View SolutionPressure inside two soap bubbles are $1.01 \, atm$ and $1.02 \, atm$. The ratio between their volumes is:
Difficult
View Solution$A$ long cylindrical glass vessel has a small hole of radius $r$ at its bottom. The depth to which the vessel can be lowered vertically in a deep water bath (surface tension $T$) without any water entering inside is
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo